The ifx_int8sub() function
The ifx_int8sub() function subtracts two int8 type values.
Syntax
mint ifx_int8sub(n1, n2, difference)
ifx_int8_t *n1;
ifx_int8_t *n2;
ifx_int8_t *difference;
- n1
- A pointer to the int8 structure that contains the first operand.
- n2
- A pointer to the int8 structure that contains the second operand.
- difference
- A pointer to an int8 structure to contain the difference of n1 and n2 (n1 - n2).
Usage
The difference value can be the same as the value of either n1 or n2.
Return values
- 0
- The subtraction was successful.
- -1284
- The subtraction resulted in overflow or underflow.