The ifx_int8copy() function
The ifx_int8copy() function copies one int8 structure to another.
Syntax
void ifx_int8copy(source, target)
ifx_int8_t *source;
ifx_int8_t *target;
- source
- A pointer to the int8 structure that contains the source int8 value to copy.
- target
- A pointer to the target int8 structure.
Return values
The ifx_int8copy() function does not return a status value. To determine the success of the copy operation, look at the contents of the int8 structure to which the target argument points.