The decadd() function

The decadd() function adds two decimal type values.

Syntax

mint decadd(n1, n2, sum)
   dec_t *n1;
   dec_t *n2;
   dec_t *sum;
n1
A pointer to the decimal structure of the first operand.
n2
A pointer to the decimal structure of the second operand.
sum
A pointer to the decimal structure that contains the sum (n1 + n2).

Usage

The sum can be the same as either n1 or n2.

Return codes

0
The operation was successful.
-1200
The operation resulted in overflow.
-1201
The operation resulted in underflow.

Example

The file decadd.ec in the demo directory contains the following sample program.
/*
   * decadd.ec *

   The following program obtains the sum of two DECIMAL numbers.
*/

#include <stdio.h>

EXEC SQL include decimal;

char string1[] = "  1000.6789"; /* leading spaces will be ignored */
char string2[] = "80";
char result[41];

main()
{
    mint x;
    dec_t num1, num2, sum;

    printf("DECADD Sample ESQL Program running.\n\n");

    if (x = deccvasc(string1, strlen(string1), &num1))
      {
      printf("Error %d in converting string1 to DECIMAL\n", x);
      exit(1);
      }
    if (x = deccvasc(string2, strlen(string2), &num2))
      {
      printf("Error %d in converting string2 to DECIMAL\n", x);
      exit(1);
      }
    if (x = decadd(&num1, &num2, &sum))
      {
      printf("Error %d in adding DECIMALs\n", x);
      exit(1);
      }
    if (x = dectoasc(&sum, result, sizeof(result), -1))
      {
      printf("Error %d in converting DECIMAL result to string\n", x);
      exit(1);
      }
    result[40] = '\0';
    printf("\t%s + %s = %s\n", string1, string2, result); /* display result */

    printf("\nDECADD Sample Program over.\n\n");
    exit(0);
}

Output

DECADD Sample ESQL Program running.

     1000.6789 + 80 = 1080.6789

DECADD Sample Program over.